06. 解决方案: While 循环

解决方案: 最大平方数 

def nearest_square(limit):
    answer = 0
    while (answer+1)**2 < limit:
        answer += 1
    return answer**2

解决方案: 断开字符串 

for headline in headlines:
    news_ticker += headline + " "
    if len(news_ticker) >= 140:
        news_ticker = news_ticker[:140]
        break

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